A 0.70 kg ball moving horizontally at 5.0


A 0.70 kg ball moving horizontally at 5.0 m/s strikes a vertical wall and rebounds with speed 2.0 m/s. What is the magnitude of the change in its linear momentum?

A 0.70 kg ball moving horizontally at 5.0

Solution:

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We can use the following equation to solve this problem.

\Delta p=m\mid v_i-v_f\mid

(Where p is the momentum change, m is mass, v_i is initial velocity, and v_f if final velocity)

 

Substitute the values given to us in the question:

\Delta p=(0.7)\mid(5-(-2)\mid

\Delta p=4.9 kg\cdotm/s

 

Final Answer:

\Delta p=4.9 kg\cdotm/s

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