A rectangle has perimeter 20 m. Express the area


A rectangle has perimeter 20 m. Express the area of the rectangle as a function of the length of one of its sides.

Solution:

Let L represent the length and W represent the width of the rectangle. Therefore, the perimeter is 2L+2W = 20m and area is A=LW.

Solve the first equation so that W is isolated.

W=\frac{20-2L}{2}=10-L.

Therefore, if we write area as a function of length, then

A(L)=L(10-L)=10L-L^{2}

We know that the lengths must be positive, so the domain of A is 0<L<10. Furthermore, because length is usually longer than the width, we can restrict it so that length must always be longer than width. Then the domain of A is 5<L<10.

 

See a mistake? Comment below so we can fix it!

Related Questions

Leave a comment

Your email address will not be published. Required fields are marked *