**Both a gage and a manometer are attached to a gas tank to measure its pressure. If the reading on the pressure gage is 80 kPa, determine the distance between the two fluid levels of the manometer if the fluid is (a) mercury (\rho=13600kg/m^{3}) or (b) water (\rho=1000kg/m^{3})**

**Solution:**

### The gage pressure and the vertical distance between the two fluid levels can be related through p_{gage}=pgh\rightarrow h=\frac{p_{gage}}{pg}

### a) Mercury: To find the distance between the two fluid levels, we will substitute values into our equation.

### h=\frac{p_{gage}}{pg}

### =\frac{80kPa}{(13600kg/m^{3})(9.81m/s^{2})}(\frac{1kN/m^{2}}{1kPa})(\frac{1000kg/m^{2}\cdot s^{2}}{1kN})

### =0.60m

### b) Water:

### h=\frac{p_{gage}}{pg}

### =\frac{80kPa}{(1000kg/m^{3})(9.81m/s^{2})}(\frac{1kN/m^{2}}{1kPa})(\frac{1000kg/m^{2}\cdot s^{2}}{1kN})

### =8.15m

In water the answer will be 8.15 m

Fixed. Thank you for pointing that out! 🙂