Determine the pressure exerted on the surface of a submarine 2


Determine the pressure exerted on the surface of a submarine cruising 175 ft below the free surface of the sea. Assume that the barometric pressure is 14.7 psia and the specific gravity of seawater is 1.03.

 

Solution:

We can find the density of water by multiplying its specific gravity by the density of sea water.

\rho =SG\times \rho_{H_{2}O}=(1.03)(62.4lbm/ft^{3})=64.27lbm/ft^{3} (SG is specific gravity, density of water can be found through research)

Now we will calculate the absolute pressure at 175ft below sea level as this is the location of the submarine.

P=P_{atm}+pgh

=(14.7psia)+(64.27lbm/ft^{3})(32.2ft/s^{2})(175ft)(\frac{1lbf}{32.2lbm\cdot ft/s^{2}})(\frac{1ft^{2}}{144in^{2}})

=92.8psia

 

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2 thoughts on “Determine the pressure exerted on the surface of a submarine

  • yared

    Thank you so much. Jesus Christ bless u .he gives this mind for you.you have to believe in the savior of jesus christ.our knowledge is nothing when we are died .to day we are life tomorrow may be died so we have believe now.