A 400-kg satellite has been placed in a circular orbit


A 400-kg satellite has been placed in a circular orbit 1500 km above the surface of the earth. The acceleration of gravity at this elevation is 6.43 m/s^2. Determine the linear momentum of the satellite, knowing that its orbital speed is 25.6\times 10^3 km/h.

Solution:

Show me the final answer↓

The acceleration due to gravity and the height do not matter when calculating the linear momentum.

Convert the orbital speed from km/h to m/s.

v=25.6\times 10^3 km/h =7111.11 m/s

 
We can use the following formula to figure out the linear momentum.

L=vm

(Where L is linear momentum, v is velocity, and m is mass)

L=(7111.11)(400)

L=2.84\times 10^6 kg·m/s

 

Final Answer:

L=2.84\times 10^6 kg·m/s

 

This question can be found in Vector Mechanics for Engineers: Statics and Dynamics, 11th edition, chapter 12, question 12.3.

Leave a comment

Your email address will not be published.