# A 400-kg satellite has been placed in a circular orbit

A 400-kg satellite has been placed in a circular orbit 1500 km above the surface of the earth. The acceleration of gravity at this elevation is 6.43 m/$s^2$. Determine the linear momentum of the satellite, knowing that its orbital speed is $25.6\times 10^3$ km/h.

#### Solution:

Show me the final answer↓

The acceleration due to gravity and the height do not matter when calculating the linear momentum.

Convert the orbital speed from km/h to m/s.

$v=25.6\times 10^3$ km/h $=7111.11$ m/s

We can use the following formula to figure out the linear momentum.

$L=vm$

(Where $L$ is linear momentum, $v$ is velocity, and $m$ is mass)

$L=(7111.11)(400)$

$L=2.84\times 10^6$ kg·m/s

#### Final Answer:

$L=2.84\times 10^6$ kg·m/s