The beam is to be hoisted using two chains


The beam is to be hoisted using two chains. Determine the magnitudes of forces F_A and F_B acting on each chain in order to develop a resultant force of 600 N directed along the positive y axis. Set θ = 45°.

The beam is to be hoisted using two chains

Image from: Hibbeler, R. C., S. C. Fan, Kai Beng. Yap, and Peter Schiavone. Statics: Mechanics for Engineers. Singapore: Pearson, 2013.

Video Solution:

Solution:

Let’s draw the vector components as follows:

The beam is to be hoisted using two chains

Now, let us draw the vectors tail to tail.

The beam is to be hoisted using two chains

We can figure out F_A and F_B using the law of sines. (Forgot the law of sines?)

\frac{F_A}{\sin 45^0}=\frac{600}{\sin 105^0}

F_A=439N

\frac{F_B}{\sin 30^0}=\frac{600}{\sin 105^0}

F_B=311N

This question can be found in Engineering Mechanics: Statics (SI edition), 13th edition, chapter 2, question 2-26.

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