Determine the current and power dissipated

Determine the current and power dissipated in the resistors

Determine the current and power dissipated

Image from: Irwin, J. David., and R. M. Nelms. Basic Engineering Circuit Analysis, Tenth Edition. N.p.: John Wiley & Sons, 2010. Print.


Looking at the diagram, we see that one of the elements  is represented in Siemens value (the 0.5 S – which represents conductance). We will first convert this into ohms. Remember that conductance, G, is equal to \frac{1}{R} where R is resistance.

Thus, we can write:



Now that we know the resistance value, we can see that all the resistors are in series, meaning you can add them up together, which gives us a total resistance value of 4\Omega.

To figure out the current, remember that current,I, is equal to voltage divided by the resistance.


Substituting the values we have gives is:



Let us now figure out the power dissipated by each resistor.

Remember that power, P=(I^2)(R)

For the both 2\Omega resistors:



This question can be found in Basic Engineering Circuit Analysis, 10th edition, chapter 1, question 2.2

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