Determine the voltage across the resistor and the power dissipated

Image from: Irwin, J. David., and R. M. Nelms. Basic Engineering Circuit Analysis, Tenth Edition. N.p.: John Wiley & Sons, 2010.

#### Solution:

### Let us first find the voltage. Voltage is V=IR where I is current and R is resistance.

### V=(2A)(12\Omega)

### V=24V

### Now, let us find the power dissipated.

### P=(I^2)(R)

### P=(2^2)(12)

### P=48W

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This question can be found in Basic Engineering Circuit Analysis, 10th edition, chapter 1, question 2.3