On a dry road, a car with good tires may

On a dry road, a car with good tires may be able to brake with a constant deceleration of 4.92 m/s^2. (a) How long does such a car, initially traveling at 24.6 m/s, take to stop? (b) How far does it travel in this time?


To solve this question, we will use the following equation:

v=v_0+at where v is final velocity, v_0 is initial velocity, a is acceleration and t is time.

a)We will now substitute the values given to us in the question. Note that v is equal to 0 because the car comes to a complete stop and the acceleration is negative because it’s deceleration.



t=5.00 s

Therefore, the time it took for the car to stop is 5 seconds.


b) To find the distance the car travels in this time, we will use the following equation:

v^2=v_0^2+2ax where x is the position or distance.

x=-\frac{(24.6 m/s)^2}{2(-4.92 m/s^2)}

x=61.5 m

Therefore, the total distance the car traveled while the brakes were applied was 61.5 m.

This question can be found in Fundamentals of Physics, 10th edition, chapter 2, question 28.

Other Problems

Leave a comment

Your email address will not be published. Required fields are marked *