If the effects of atmospheric resistance are accounted for

If the effects of atmospheric resistance are accounted for, a falling body has an acceleration defined by the equation a = 9.81[1-v^2(10^{-4})] m/s^2, where is v in m/s and the positive direction is downward. If the body is released from rest at a very high altitude, determine (a) the velocity when t = 5 s, and (b) the body’s terminal or maximum attainable velocity (as t\rightarrow\infty).


Show me the final answer↓

Remember that we can write acceleration as:




Let us take the integral of both sides of the equation:

\,\displaystyle \int^{t_2}_{t_1}dt=\int^{v}_{v_0}\dfrac{1}{a(v)}dv


Substitute our acceleration equation:

\,\displaystyle \int^{t}_{0}dt=\int^{v}_{0}\dfrac{1}{9.81[1-v^2(10^{-4})]}dv


Isolate for v:



At t=5 seconds, we have:


v=45.5 m/s


As t\rightarrow\infty, we have:

v=100 m/s


Final Answers:

v=45.5 m/s

Maximum velocity, v=100 m/s
This question can be found in Engineering Mechanics: Dynamics (SI edition), 13th edition, chapter 12, question 12-21.

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