An electron has a constant acceleration of +3.2 m/s^2. At a certain instant its velocity is 9.6 m/s. What is its velocity (a) 2.5 s earlier and (b) 2.5 s later?
To solve this question, we will use the following equation:
(where v is final velocity, v_0 is initial velocity, a is acceleration, and t is time.)
a) To find the velocity before 2.5 seconds, we will set t=-2.5 s. Thus, we have:
b) To find the speed after 2.5 seconds, we will set t=+2.5 s. Thus, we have: