Find Io in the circuit in Fig. P3.7 using nodal analysis.

#### Solution:

Show me the final answerâ†“

Let us label the nodes we will use to perform nodal analysis as follows:

In the following equations, k=10^3 and m=10^{-3}

We will now write a KCL equation at node V_1, the orange node:

I_1+I_2+4m=0

Let us express these currents in terms of voltage and resistance using I=\dfrac{V}{R}.

\dfrac{V_1}{1k}+\dfrac{V_1-V_2}{2k}+4m=0\,\,\,\color{orange} {\text{(eq.1)}}

Now, we shift our focus to the second node, V_2 (purple node).

Again, we will write a KCL equation.

I_3+I_4=6m

Expressing the currents in terms of voltage and resistance gives us:

\dfrac{V_2-V_1}{2k}+\dfrac{V_2}{2k}=6m\,\,\,\color{purple} {\text{(eq.2)}}

Solving equations 1 and 2 simultaneously gives us (see full steps):

V_1=-0.8 v

V_2=5.6 v

V_2=5.6 v

We know I_0=I_2. Writing I_2 in terms of voltage and resistance gives us:

I_0=\dfrac{V_1-V_2}{2k}

I_0=\dfrac{-0.8-5.6}{2k}

I_0=\dfrac{-6.4}{2k}

I_0=-3.2 mA

I_0=\dfrac{-0.8-5.6}{2k}

I_0=\dfrac{-6.4}{2k}

I_0=-3.2 mA

(A negative current value means the direction of the current flow is opposite to the direction shown in the circuit diagram.)

#### Final Answer:

I_0=-3.2 mA