Find Io in the circuit

Find Io in the circuit in Fig. P3.7 using nodal analysis.

Image from: J. D. Irwin and R. M. Nelms, Basic engineering circuit analysis, 10th ed. Hoboken, NJ: John Wiley, 2011.

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Let us label the nodes we will use to perform nodal analysis as follows:

In the following equations,

k=10^3

and

m=10^{-3}

We will now write a KCL equation at node $V_1$ , the orange node:

I_1+I_2+4m=0

Let us express these currents in terms of voltage and resistance using $I=\dfrac{V}{R}$ .

\dfrac{V_1}{1k}+\dfrac{V_1-V_2}{2k}+4m=0\,\,\,\color{orange} {\text{(eq.1)}}

Now, we shift our focus to the second node, $V_2$ (purple node).

Again, we will write a KCL equation.

I_3+I_4=6m

Expressing the currents in terms of voltage and resistance gives us:

\dfrac{V_2-V_1}{2k}+\dfrac{V_2}{2k}=6m\,\,\,\color{purple} {\text{(eq.2)}}

Solving equations 1 and 2 simultaneously gives us (see full steps):

V_1=-0.8

V_2=5.6

We know $I_0=I_2$ . Writing $I_2$ in terms of voltage and resistance gives us:

I_0=\dfrac{V_1-V_2}{2k}

I_0=\dfrac{-0.8-5.6}{2k}

I_0=\dfrac{-6.4}{2k}

I_0=-3.2

(A negative current value means the direction of the current flow is opposite to the direction shown in the circuit diagram.)

I_0=-3.2