The load has a mass of 15 kg and is lifted by the pulley system shown. Determine the force F in the cord as a function of the angle θ. Plot the function of force F versus the angle θ for 0 ≤ θ ≤ 90°.

#### Solution:

We will first draw a free body diagram like so:

It is important to note that because we are assuming the pulleys to be frictionless, the **tension throughout the cord is constant**.

Let us write an equation of equilibrium for the y-axis forces.

+\uparrow \sum \text{F}_\text{y}\,=\,0

F\text{cos}\theta\,+\,F\text{cos}\theta\,-\,147.15\,=\,0

F\text{cos}\theta\,+\,F\text{cos}\theta\,-\,147.15\,=\,0

(Isolate for F)

F\,=\,\dfrac{73.575}{\text{cos}\theta}

We can now graph this function like so: