If each one of the ropes will break 6

If each one of the ropes will break when it is subjected to a tensile force of 450 N, determine the maximum uplift force F the balloon can have before one of the ropes breaks.

If each one of the ropes will break

Image from: Hibbeler, R. C., S. C. Fan, Kai Beng. Yap, and Peter Schiavone. Statics: Mechanics for Engineers. Singapore: Pearson, 2013.


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To solve this problem, we must first express the force in each rope in Cartesian vector form. To do so, we have to first write the locations of points A, B, C and D in Cartesian vector form.

If each one of the ropes will break

Using the diagram, we can locate the points are write them in Cartesian vector form:

A:(0i+0j+6k) m

B:(-1.5i-2j+0k) m

C:(2i-3j+0k) m

D:(0i+2.5j+0k) m


The position vectors for each rope are:




A position vector, denoted \mathbf{r} is a vector beginning from one point and extending to another point. It is calculated by subtracting the corresponding vector coordinates of one point from the other. If the coordinates of point A was (x_A,y_A,z_A) and the coordinates of point B was(x_B,y_B,z_B), then r_{AB}\,=\,(x_B-x_A)i+(y_B-y_A)j+(z_B-z_A)k


The magnitude of each position vector is:

magnitude of r_{AB}\,=\,\sqrt{(-1.5)^2+(-2)^2+(-6)^2}\,=\,6.5

magnitude of r_{AC}\,=\,\sqrt{(2)^2+(-3)^2+(-6)^2}\,=\,7

magnitude of r_{AD}\,=\,\sqrt{(0)^2+(2.5)^2+(-6)^2}\,=\,6.5

The magnitude is equal to the square root of the sum of the squares of the vector. If the position vector was r\,=\,ai+bj+ck, then the magnitude would be, r_{magnitude}\,=\,\sqrt{(a^2)+(b^2)+(c^2)}. In the simplest sense, you take each term of a vector, square it, add it together, and then take the square root of that value.


The unit vectors are:




The unit vector is each corresponding unit of the position vector divided by the magnitude of the position vector. If the position vector was r\,=\,ai+bj+ck, then unit vector, u\,=\,\dfrac{a}{\sqrt{(a^2)+(b^2)+(c^2)}}+\dfrac{b}{\sqrt{(a^2)+(b^2)+(c^2)}}+\dfrac{c}{\sqrt{(a^2)+(b^2)+(c^2)}}


We can now express each force in Cartesian vector form:




(further simplify this by expanding the brackets using FOIL and simplifying the fractions into decimal values)





(Force F is the net uplift force, which is applied directly upwards, thus it only has a z-component)


We can now write our equations of equilibrium. All forces added together must equal zero.

\sum \text{F}\,=\,0


Since all forces added together must equal zero, then all individual components (x, y, z-components) added together must also equal zero.








The question states that the maximum tension a cable can withstand is 450 N, therefore, we will assume that rope AD, i.e F_{AD} has a force value of 450 N. Substituting 450 N for F_{AD} gives us the following equations:








Solving the three equations gives us:

F_{AB}\,=\,264.7 N

F_{AC}\,=\,213.8 N

F\,=\,842.9 N

Notice how both tensions in the cables are less than 450 N. That means the assumption we made is correct. If, however, we got tension values higher than 450 N for the other two cables, then we would have to change our assumption and assume another cable is 450 N.


This question can be found in Engineering Mechanics: Statics (SI edition), 13th edition, chapter 3, question 3-49.

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