A stone A is dropped from rest down a well, and in 1 s another stone B is dropped from rest. Determine the distance between the stones another second later.
Show me the final answer↓
We will calculate the distance the first stone travels in 2 seconds, and we will calculate the distance the second stone traveled in 1 second. We will then subtract the difference to figure out the distance between them. To do so, we will use the following equation:
(Where s_2 is final displacement, s_1 is initial displacement, v_1 is initial velocity, t is time, and a_c is constant acceleration)
From the question, we know the following:
t=2 s (For the first stone)
t=1 s (For the second stone)
Let us use our equation to calculate the distance the first stone traveled.
Now, we will calculate the distance the second stone traveled.
We can now calculate the difference between the two: