The square surface shown measures 3.2 mm on each side. It is immersed in a uniform electric field with magnitude E = 1800 N/C and with field lines at an angle of θ = 35° with a normal to the surface, as shown. Take that normal to be directed “outward,” as though the surface were one face of a box. Calculate the electric flux through the surface.
(Where E is electric field, \theta is the angle between our area vector and electric field lines, and A is area)
(As the field lines are at an angle of 35^0, our normal to surface must be at an angle of 180^0-35^0=145^0. This calculates the angle between the electric field lines and our area vector.)