When an electron moves from A to B along an electric field 4


When an electron moves from A to B along an electric field line, the electric field does 3.94\times10^{-9}J  of work on it. What are the electric potential differences (a) V_{B}-V_{A} (b) V_{C}-V_{A} and (c) V_{C}-V_{B}?

When an electron moves from A to B along an

 

Solution:

Note that equipotential surfaces will always be perpendicular to the electric field lines. The figure above shows the electric field lines and the equipotential surfaces for a uniform electric field.

a) V_{B} - V_{A} = \triangle \frac{U}{q} = \frac{-W}{-e} = \frac{-(3.94 \times 10^{-19} J)}{(-1.60\times10^{-19} C)} = 2.46 V

b)Note that V_{C} - V_{A} = V_{B} - V_{A} = 2.46V

c)V_{C} - V_{B} = 0 because B and C are on the same equipotential line.

 

See a mistake? Comment below so we can fix it!

Leave a comment

Your email address will not be published.

4 thoughts on “When an electron moves from A to B along an electric field